How to get the no of Days from the difference of two dates in PostgreSQL? -


select extract(day age('2013-04-06','2013-04-04'));` 

gives me no of days ! i.e.: 2 days

but failed when have differnt month:

select extract(day age('2013-05-02','2013-04-01')); 

so need no of days 32 days

subtraction seems more intuitive.

select '2013-05-02'::date - '2013-04-01'::date 

run query see why result 31 instead of 32

with dates (   select generate_series('2013-04-01'::date, '2013-05-02'::date, '1 day')::date end_date,                          '2013-04-01'::date start_date ) select end_date, start_date, end_date - start_date difference dates order end_date 

the difference between today , today 0 days. whether matters application-dependent. can add 1 if need to.


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