Laravel: How to respond with custom 404 error depending on route -

i'm using laravel4 framework , came across problem.

i want display custom 404 error depending on requested url.

for example:

route::get('site/{something}', function($something){     return view::make('site/error/404'); }); 

and

route::get('admin/{something}', function($something){     return view::make('admin/error/404'); }); 

the value of '$something' not important.

shown example works 1 segment, i.e. 'site/foo' or 'admin/foo'. if request 'site/foo/bar' or 'admin/foo/bar' laravel throw default 404 error.

app::missing(function($exception){     return '404: page not found'; }); 

i tried find in laravel4 documentation nothing right me. please :)

thank you!

in app/start/global.php

app::missing(function($exception)  {     if (request::is('admin/*'))     {         return response::view('admin.missing',array(),404);     }     else if (request::is('site/*'))     {         return response::view('site.missing',array(),404);     }     else     {          return response::view('default.missing',array(),404);     } }); 

in view, can find $something {{ request::path(); }} or {{ request::segment(); }}