python - Remove call() when using Mock -

in python 2.6 or 2.7, want rid of 'call' stuff when using mock.call_args_list.

i want check if mock called when argument.

i have like:

a = mock() ... self.assertequal(a.call_args_list, ...) 

but call_args_list looks like:

[call(arg1, arg2, arg3), call(...)] 

how can access arg2 value precisely without recreating complete call object?

if there way iterate in "call" object , list of argument , extract whatever need?

the thing had no problem, call_args_list returned me lists without "call" stuff , able wanted do, reason "call" started appearing , don't know how handle correctly.

you can do:

>>> import mock >>> my_call = mock.call('test', example=3) >>> name, args, kwargs = my_call >>> name '' >>> args ('test',) >>> kwargs {'example': 3} 

this give name (not available), positional arguments , keyword arguments of call. according the documentation, call() objects in call_args_list tuples 2 values, not three. can do:

>>> args, kwargs = my_call 

you can use indexing values. example, my_call[2] give keyword arguments. can used convert call_args_list arguments:

>>> call1 = mock.call('test', example=3) >>> call2 = mock.call('test', example=4, value=5) >>> call_args_list = [call1, call2] >>> [(item[1], item[2]) item in call_args_list] [(('test',), {'example': 3}), (('test',), {'example': 4, 'value': 5})]