c - how to make loop in this case? -

i need compute first 100 prime numbers, in output got "9" , other in numbers....................... want compute first 100 prime numbers

{ bool prime; int start, new, kor,k, i,gg; start=1;  k=1 ; gg=0;  {       if (start < 2) {new = 2;}     if (start == 2) {new = 3;}     if (start > 2) {          if ((new % 2) == 0)          new--;          {             prime  = true;              kor=sqrt(new);              new+=2;             (i=3;prime&& (i<=kor); i+=2) {                             if (new % == 0)                                  prime=false;}         } while (!prime) ;         }       gg++;     printf("%d->%d\n",gg, new);     k++;     start++;     continue; }      while (k<101);  } 

with

if (start < 2) {new = 2;} if (start == 2) {new = 3;} 

you have special cases first , second numbers. next time round do...while loop skip loop because kor 1, thereby printing 5. didn't check, perhaps got lucky. smells don't check far enough.

next time, after

kor=sqrt(new1); new1+=2; 

kor 2, again don't loop, , print 7. next time have same situation. kor still 2 9.

i think if switch new+=2 before kor=sqrt(1); work. once in part, don't need check if even, since add 2 odd number. btw why continue last thing in loop? might better (i took liberty of putting in function):

void find_primes() {     bool prime; int start, new, kor,k, i,gg;     start=1; k=1 ;gg=0;           {          if (start < 2) {new = 2;}         if (start == 2) {new = 3;}         if (start > 2) {              {                 prime = true;                 new+=2;                 kor=sqrt(new);                 (i=3;prime&& (i<=kor); i+=2) {                     if (new % == 0)                          prime=false;                 }             }              while (!prime) ;         }         gg++; printf("%d->%d\n",gg, new);          k++;         start++;     }     while (k<101); }